2018-09-18 重点归纳
美国数学竞赛AMC8专为8年级及以下的初中学生设计,但近年来的数据显示,越来越多小学4-6年级的考生加入到美国数学竞赛AMC8级别的考试行列中,而当这些学生能在成绩中取得“A”类标签,则是对孩子数学天赋的优势证明,不管是对美高申请还是今后在数学领域的发展都极其有利!那么接下来跟随小编来看一下美国数学竞赛AMC8的官方真题以及官方解答吧:
The circumference of the circle with center  is divided into
 is divided into  equal arcs, marked the letters
 equal arcs, marked the letters  through
 through  as seen below. What is the number of degrees in the sum of the angles
 as seen below. What is the number of degrees in the sum of the angles  and
 and  ?
?


For this problem, it is useful to know that the measure of an inscribed angle is half the measure of its corresponding central angle. Since each unit arc is  of the circle's circumference, each unit central angle measures
 of the circle's circumference, each unit central angle measures  . Then, we know that the inscribed arc of
. Then, we know that the inscribed arc of  so
 so  ; and the inscribed arc of
; and the inscribed arc of  so
 so  .
. 
The "Middle School Eight" basketball conference has  teams. Every season, each team plays every other conference team twice (home and away), and each team also plays
 teams. Every season, each team plays every other conference team twice (home and away), and each team also plays  games against non-conference opponents. What is the total number of games in a season involving the "Middle School Eight" teams?
 games against non-conference opponents. What is the total number of games in a season involving the "Middle School Eight" teams?

Within the conference, there are 8 teams, so there are  pairings of teams, and each pair must play two games, for a total of
 pairings of teams, and each pair must play two games, for a total of  games within the conference.
 games within the conference.
Each team also plays 4 games outside the conference, and there are 8 teams, so there are a total of  games outside the conference.
 games outside the conference.
Therefore, the total number of games is  , so
, so  is our answer.
 is our answer.
以上就是小编对AMC 8数学竞赛官方真题以及解析的介绍,希望对你有所帮助,更多AMC官方真题及学习资料请持续关注AMC数学竞赛网!
 
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